Answer to #31: Answer: His daughters are 8, 3, and 3. The prime factorization of 72 is 2 * 2 * 2 * 3 * 3, so the possible ages are 2, 3, 4, 6, 8, 9, 12, and 18. Using the prime factorization and these numbers the only combinations of numbers that work for the first clue are:
18, 2 and 2.
9, 4 and 2.
6, 6 and 2.
6, 4 and 3.
8, 3, and 3.
Since he doesn't know the ages after this piece of information the sum of the three numbers must not be unique. The sum of 8, 3, and 3; and 6, 6, and 2 are the same. Now the final clue comes in handy. Since we know that the oldest daughter has her own bed it is likely that she has the bed to herself and is older than the other two so there ages are 8, 3, and 3 rather than 2, 6 and 6.
Riddle: A man is writing his will and he wants to leave everything he has to one of his two sons, whichever one is more dedicated. To decide which one will win his fortune he gives them each a car and tells them that whoever's car passes the finish line he has set up last will get everything he has.
After a month of both sons refusing to cross the line they finally go to their uncle for advice. They both leave their uncles house in a hurry and race to the finish line as fast as they can.
What advice did their uncle give? [Slide for answer]
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