Part 17 In MATHEVERSUM

Start from the beginning
                                    

= 2C^2

2. so HYPERCUBE-C^3 is: 

2 times lower in the fourth dimension

3. thus the tilt of HYPERCUBE-C^3 from the fourth dimension is: 

86.6%

Pic.23

As a result, HYPERCUBE-C^3 moves mathematically also in some direction of the three-dimensionality of MATHEVERSUM at mathematical speed 86

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As a result, HYPERCUBE-C^3 moves mathematically also in some direction of the three-dimensionality of MATHEVERSUM at mathematical speed 86.6%c.

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A note here:

I marked the speed in the three-dimensionality of MATHEVERSUM with lowercase letter c because this speed is not a mathematical force, but it only results from the change in the direction of HYPERCUBE-C^3's movement in the four-dimensionality of MATHEVERSUM.

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c) Yet somewhere else in MATHEVERSUM it is like that:

Pic.25

In this case, in some direction of the three-dimensionality, on "red" CUBE-C^2 is pressing mathematical "pink" energy of:

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In this case, in some direction of the three-dimensionality, on "red" CUBE-C^2 is pressing mathematical "pink" energy of:

{[3 * KAZIUK * (STRINGOR)] / [(SHORTEK * KAZIUK)^2 * SHORTEK]} * SPEED-C =

= 3C^2

And now the total mathematical force pressing jointly on HYPERCUBE-C^3 is:

"red" C^2 + "pink" 3C^2 =

= 4C^2

It makes that:

1. HYPERCUBE-C^3 is tilted in such a way that the density in it is: 

4 times greater

and it is:

{[4 * KAZIUK * (STRINGOR)] / [(SHORTEK * KAZIUK)^2 * SHORTEK]} * SPEED-C

it's because:

{[4 * KAZIUK * (STRINGOR)] / [(SHORTEK * KAZIUK)^2 * SHORTEK]} * SPEED-C =

= 4C^2

2. so HYPERCUBE-C^3 is: 

4 times lower in the fourth dimension

3. thus the tilt of HYPERCUBE-C^3 from the fourth dimension is: 

96.82%

Pic.26

As a result, HYPERCUBE-C^3 moves mathematically also in some direction of the three-dimensionality of MATHEVERSUM at mathematical speed 96

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As a result, HYPERCUBE-C^3 moves mathematically also in some direction of the three-dimensionality of MATHEVERSUM at mathematical speed 96.82%c.

Pic.27

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